have you been reading through my programming riddles?
have they been too easy for you?
try the python challenge. let me know how far you made it
have you been reading through my programming riddles?
have they been too easy for you?
try the python challenge. let me know how far you made it
what’s the shortest anagram detector you know how to write, in javascript?
there must be a shorter way to do this. highlight below to see a solution.
var anagramDetector = function (x,y) {
if (x.length != y.length) return false;
var alpha_x = x.split("").sort().join("");
var alpha_y = y.split("").sort().join("");
for ( j = 0; j<y.length;++j) {
if (alpha_x[j] != alpha_y[j]) return false;
}
return true;
}
PS: there’s a cool method for solving this for a fixed alphabet, using primes
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what’s the shortest anagram detector you know how to write, in python?
this is one that keeps feeling like it should be a one liner (because it’s very similar to this one liner), but i suspect can’t be done in one line
highlight to see a solution.
def fn(x,y):
if len(x) != len(y):
return False
for i in x:
y = y.replace(i,'',1)
return not len(y) > 0
PS: there’s a cool method for solving this for a fixed alphabet, using primes
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how well do you know your arrays?
figure out what you think each line does, and then check yourself by running them in a console
test = [1,2,3] test test.length test.length = 5 test.length test
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javascript riddle
does null == false?
if (null) { console.log("null"); } if (null == false) { console.log("null == false"); } if (!null) { console.log("!null"); }
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javascript riddle #4
true or false?
['a','b'] < ['a','b'] ['a','b'] <= ['a','b'] ['a','b'] == ['a','c'] ['a','b'] >= ['a','c'] ['a','b'] > ['a','c'] ['a','b'] = ['a','b'] ['a','b'] == ['a','b'] ['a','b'] === ['a','b']
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python riddle
def fn(): x = "Who's on first" def f(y): return x+y x = "What's on second" return f("?") print fn()
(ok, so this is more of a mnemonic to help me remember how python works)
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how well do you know your “null”s and “undefined”s?
write down what you expect the result of each operation to be. run them in a javascript console (Chrome, Firefox/Firebug, Safari). compare, verify, contrast, and, for fun, give yourself a score out of “3/4 donut”.
// Equality null == undefined null === undefined !null == !undefined !null === !undefined // addition and concatenation null + '' undefined + '' null + 1 undefined + 1 // fun with enumerations test = []; test.push(null); console.log(test) test = []; test.push(undefined); console.log(test) {null:2} {undefined:2} {a:null} {a:undefined}
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javascript riddle
see if you can explain what exactly is going on here, and why
7 > 5 > 3
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python riddle
def listMutator(arglist): arglist = ["mutated"] print "arglist: ", arglist test = ["not mutated"] listMutator(test) print "test: ", test
Bonus question – when is the following statement True, and when is it False?
-7/6 == -(7/6)
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